What is the integral from 1 to 7 of (sqrt(x)+x^3)/x ?

The integral from 1 to 7 of (sqrt(x)+x^3)/x is 2sqrt(7)+112

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integral from 1 to 7 of (sqrt(x)+x^3)/x

\int_{1}^{7} \frac{x + x ^{3}}{x} d x

27 + 112

Solution steps

\int_{1}^{7} \frac{x + x ^{3}}{x} d x

Expand

\frac{x + x ^{3}}{x} : \frac{1}{x} + x^{2}

= \int_{1}^{7} \frac{1}{x} + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{7} \frac{1}{x} d x + \int_{1}^{7} x^{2} d x

\int_{1}^{7} \frac{1}{x} d x = 27 - 2

\int_{1}^{7} x^{2} d x = 114

= 27 - 2 + 114

Simplify

= 27 + 112

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What is the integral from 1 to 7 of (sqrt(x)+x^3)/x ?
The integral from 1 to 7 of (sqrt(x)+x^3)/x is 2sqrt(7)+112