What is the integral from 0 to 1 of-t ?

The integral from 0 to 1 of-t is -1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of-t

\int_{0}^{1} - t d t

- \frac{1}{2}

Solution steps

\int_{0}^{1} - t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{1} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{0}^{1}

= - [\frac{t ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= - \frac{1}{2}

\int_{- 1}^{x} e^{y^{2}} d y

\int_{- a}^{a} x^{2} d x

\int_{4}^{9} 2 x (10 x + 3) d x

\int_{0}^{2} (2 x) d x

\int_{0}^{\frac{π}{2}} 4 sin (x) d x