What is the integral from 0 to 1 of (x^2)^2 ?

The integral from 0 to 1 of (x^2)^2 is 1/5

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integral from 0 to 1 of (x^2)^2

\int_{0}^{1} (x^{2})^{2} d x

\frac{1}{5}

Decimal Notation

0.2

Solution steps

\int_{0}^{1} (x^{2})^{2} d x

Simplify

(x^{2})^{2} : x^{4}

= \int_{0}^{1} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{0}^{1}

= [\frac{x ^{5}}{5}]_{0}^{1}

Compute the boundaries:

\frac{1}{5}

= \frac{1}{5}

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What is the integral from 0 to 1 of (x^2)^2 ?
The integral from 0 to 1 of (x^2)^2 is 1/5