What is the integral from 0 to pi of (2+cos(x)) ?

The integral from 0 to pi of (2+cos(x)) is 2pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi of (2+cos(x))

\int_{0}^{π} (2 + cos (x)) d x

2 π

Decimal Notation

6.28318 \dots

Solution steps

\int_{0}^{π} 2 + cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 2 d x + \int_{0}^{π} cos (x) d x

\int_{0}^{π} 2 d x = 2 π

\int_{0}^{π} cos (x) d x = 0

= 2 π + 0

Simplify

= 2 π

\int_{1}^{6} (5 x + 1) d x

\int_{0}^{4} (x - 2)^{2} d x

\int_{1}^{8} 1 + \frac{81}{16} x d x

\int_{\frac{1}{3}}^{3} (1 - \frac{1}{x ^{2}}) d x

\int_{1}^{9} x^{2} + 2 d x

What is the integral from 0 to pi of (2+cos(x)) ?
The integral from 0 to pi of (2+cos(x)) is 2pi