What is the integral from 4.6 to 7 of (12x^2-6x+4) ?

The integral from 4.6 to 7 of (12x^2-6x+4) is 908.73599…

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integral from 4.6 to 7 of (12x^2-6x+4)

\int_{4.6}^{7} (12 x^{2} - 6 x + 4) d x

908.73599 \dots

Solution steps

\int_{4.6}^{7} 12 x^{2} - 6 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4.6}^{7} 12 x^{2} d x - \int_{4.6}^{7} 6 x d x + \int_{4.6}^{7} 4 d x

\int_{4.6}^{7} 12 x^{2} d x = 982.65599 \dots

\int_{4.6}^{7} 6 x d x = 83.52

\int_{4.6}^{7} 4 d x = 9.6

= 982.65599 \dots - 83.52 + 9.6

Simplify

= 908.73599 \dots

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What is the integral from 4.6 to 7 of (12x^2-6x+4) ?
The integral from 4.6 to 7 of (12x^2-6x+4) is 908.73599…