What is the integral from 0 to 4 of (1/(sqrt(9))) ?

The integral from 0 to 4 of (1/(sqrt(9))) is 4/3

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integral from 0 to 4 of (1/(sqrt(9)))

\int_{0}^{4} (\frac{1}{9}) d x

\frac{4}{3}

Decimal Notation

1.33333 \dots

Solution steps

\int_{0}^{4} \frac{1}{9} d x

Integral of a constant:

\int a d x = a x

= [\frac{1}{9} x]_{0}^{4}

9 = 3

= [\frac{1}{3} x]_{0}^{4}

Compute the boundaries:

\frac{4}{3}

= \frac{4}{3}

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What is the integral from 0 to 4 of (1/(sqrt(9))) ?
The integral from 0 to 4 of (1/(sqrt(9))) is 4/3