What is the integral from x^2 to 1 of 1 ?

The integral from x^2 to 1 of 1 is 1-x^2

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integral from x^2 to 1 of 1

\int_{x^{2}}^{1} 1 d x

1 - x^{2}

Solution steps

\int_{x^{2}}^{1} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{x^{2}}^{1}

Simplify

= [x]_{x^{2}}^{1}

Compute the boundaries:

1 - x^{2}

= 1 - x^{2}

\int_{0}^{t} \frac{1}{x + 10} d x

\int_{0}^{2} x^{2} - 4 x + 4 d x

\int_{1}^{e^{2}} (ln (x))^{2} d x

\int_{0}^{1} \frac{1}{( 5 - 3 x ) ^{2}} d x

\int_{3}^{1} x d x

What is the integral from x^2 to 1 of 1 ?
The integral from x^2 to 1 of 1 is 1-x^2