What is the derivative of 2/((x-1^3)) ?

The derivative of 2/((x-1^3)) is -6/((x-1)^4)

What is the first derivative of 2/((x-1^3)) ?

The first derivative of 2/((x-1^3)) is -6/((x-1)^4)

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\frac{d}{d x} (\frac{2}{( x - 1 ) ^{3}})

- \frac{6}{( x - 1 ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{2}{( x - 1 ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{( x - 1 ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x - 1)^{- 3})

Apply the chain rule:

- \frac{3}{( x - 1 ) ^{4}} \frac{d}{d x} (x - 1)

= - \frac{3}{( x - 1 ) ^{4}} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 2 (- \frac{3}{( x - 1 ) ^{4}} \cdot 1)

Simplify

2 (- \frac{3}{( x - 1 ) ^{4}} \cdot 1) : - \frac{6}{( x - 1 ) ^{4}}

= - \frac{6}{( x - 1 ) ^{4}}

\frac{2 \cdot ( s - 1 ) \cdot e ^{- 2 s}}{s ^{2} - 2 s + 2}

y = x^{2} + 2, (- 4, 18)

y = 7 x, y = \frac{7}{4} x, y = 78 - x^{2}

\frac{\partial}{\partial t} (r \cdot cos (t))

ln (, at^{c})

What is the derivative of 2/((x-1^3)) ?
The derivative of 2/((x-1^3)) is -6/((x-1)^4)
What is the first derivative of 2/((x-1^3)) ?
The first derivative of 2/((x-1^3)) is -6/((x-1)^4)