What is the integral from 1 to 5 of 1/(x^3) ?

The integral from 1 to 5 of 1/(x^3) is 12/25

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integral from 1 to 5 of 1/(x^3)

\int_{1}^{5} \frac{1}{x ^{3}} d x

\frac{12}{25}

Decimal Notation

0.48

Solution steps

\int_{1}^{5} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{5}

= [- \frac{1}{2 x ^{2}}]_{1}^{5}

Compute the boundaries:

\frac{12}{25}

= \frac{12}{25}

\int_{1}^{3} (x^{2} + 3) d x

\int_{1}^{5} x^{2} - 2 x - 8 d x

\int_{0}^{4} cos (x) d x

\int_{1}^{1} tan (t) d t

\int_{0}^{3} (- x^{2} - 3 x) d x

What is the integral from 1 to 5 of 1/(x^3) ?
The integral from 1 to 5 of 1/(x^3) is 12/25