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Popular >

integral from 0 to 2 of-2x+4

Solution

\int_{0}^{2} - 2 x + 4 d x

Solution

4

Solution steps

\int_{0}^{2} - 2 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} 2 x d x + \int_{0}^{2} 4 d x

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 4 d x = 8

= - 4 + 8

Simplify

= 4

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\int_{1}^{5} 5 x d x

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\int_{0}^{14} 196 - x^{2} d x

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\int_{0}^{\frac{π}{4}} (1 + e^{t a n (x)}) sec^{2} (x) d x

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\int_{1}^{6} 2 x - 6 d x

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\int_{0}^{1} \frac{1 + x ^{2}}{1 + y ^{2}} d y

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of-2x+4 ?
The integral from 0 to 2 of-2x+4 is 4