What is the integral from 0 to a of 1/x ?

The integral from 0 to a of 1/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to a of 1/x

\int_{0}^{a} \frac{1}{x} d x

diverges

Solution steps

\int_{0}^{a} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{0}^{a}

Compute the boundaries:

diverges

= diverges

\int_{0}^{4} (4 x^{2} + x) d x

\int_{1}^{5} \frac{8}{x} d x

\int_{- 5}^{4} x^{2} + 5 - x d x

\int_{1}^{x} \frac{1}{1 + t ^{2}} d t

\int_{0}^{\frac{π}{4}} sin^{2} (\frac{x}{2}) d x

What is the integral from 0 to a of 1/x ?
The integral from 0 to a of 1/x is diverges