What is the integral from 99 to 100 of (x^2+1) ?

The integral from 99 to 100 of (x^2+1) is 29704/3

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integral from 99 to 100 of (x^2+1)

\int_{99}^{100} (x^{2} + 1) d x

\frac{29704}{3}

Decimal Notation

9901.33333 \dots

Solution steps

\int_{99}^{100} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{99}^{100} x^{2} d x + \int_{99}^{100} 1 d x

\int_{99}^{100} x^{2} d x = \frac{29701}{3}

\int_{99}^{100} 1 d x = 1

= \frac{29701}{3} + 1

Simplify

\frac{29701}{3} + 1 : \frac{29704}{3}

= \frac{29704}{3}

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What is the integral from 99 to 100 of (x^2+1) ?
The integral from 99 to 100 of (x^2+1) is 29704/3