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Popular >

integral from 1 to 5 of (x+1)

Solution

\int_{1}^{5} (x + 1) d x

Solution

16

Solution steps

\int_{1}^{5} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x d x + \int_{1}^{5} 1 d x

\int_{1}^{5} x d x = 12

\int_{1}^{5} 1 d x = 4

= 12 + 4

Simplify

= 16

Popular Examples

integral from 0 to pi/2 of x-sin(x)

\int_{0}^{\frac{π}{2}} x - sin (x) d x

integral from-1 to 2 of x/(sqrt(x+2))

\int_{- 1}^{2} \frac{x}{x + 2} d x

integral from 0 to x/2 of sin(2t)

\int_{0}^{\frac{x}{2}} sin (2 t) d t

integral from 1 to 5 of xsqrt(x-1)

\int_{1}^{5} x x - 1 d x

integral from 0 to 1 of ((e^x+2))/(e^x)

\int_{0}^{1} \frac{( e ^{x} + 2 )}{e ^{x}} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 5 of (x+1) ?
The integral from 1 to 5 of (x+1) is 16