What is the integral from 0 to pi of (3sin(x)) ?

The integral from 0 to pi of (3sin(x)) is 6

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integral from 0 to pi of (3sin(x))

\int_{0}^{π} (3 sin (x)) d x

6

Solution steps

\int_{0}^{π} 3 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 3 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 3 \cdot 2

Simplify

= 6

\int_{1}^{5} \frac{3 ( ln ( x ) ) ^{2}}{x} d x

\int_{0}^{2} \frac{x ( 1 + 3 y ^{2} )}{4} d x

\int_{1}^{2} x^{2} y d y

\int_{2}^{5} 2 d x

\int_{0}^{\frac{π}{4}} cos (x^{2}) d x

What is the integral from 0 to pi of (3sin(x)) ?
The integral from 0 to pi of (3sin(x)) is 6