What is the integral from-1 to 0 of xe^{-x} ?

The integral from-1 to 0 of xe^{-x} is -1

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integral from-1 to 0 of xe^{-x}

\int_{- 1}^{0} x e^{- x} d x

- 1

Solution steps

\int_{- 1}^{0} x e^{- x} d x

Apply Integration By Parts

: [- e^{- x} x - \int - e^{- x} d x]_{- 1}^{0}

= [- e^{- x} x - \int - e^{- x} d x]_{- 1}^{0}

\int - e^{- x} d x = e^{- x}

= [- e^{- x} x - e^{- x}]_{- 1}^{0}

Compute the boundaries:

- 1

= - 1

\int_{e}^{e^{3}} \frac{ln ( x )}{x} d x

\int_{2}^{2} 1

\int_{x^{2}}^{x} \frac{x}{y} d y

\int_{1}^{2} \frac{x ^{2} + 5}{x} d x

\int_{- 2}^{1} x + 1 d x

What is the integral from-1 to 0 of xe^{-x} ?
The integral from-1 to 0 of xe^{-x} is -1