What is the integral from 1 to 2 of f(t) ?

The integral from 1 to 2 of f(t) is (3f)/2

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integral from 1 to 2 of f(t)

\int_{1}^{2} f (t) d t

\frac{3 f}{2}

Solution steps

\int_{1}^{2} f t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{1}^{2} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{1}^{2}

= f [\frac{t ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= f \frac{3}{2}

Simplify

= \frac{3 f}{2}

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What is the integral from 1 to 2 of f(t) ?
The integral from 1 to 2 of f(t) is (3f)/2