What is the integral from-pi/3 to 0 of sin(x) ?

The integral from-pi/3 to 0 of sin(x) is -1/2

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integral from-pi/3 to 0 of sin(x)

\int_{- \frac{π}{3}}^{0} sin (x) d x

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

\int_{- \frac{π}{3}}^{0} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- \frac{π}{3}}^{0}

Compute the boundaries:

- \frac{1}{2}

= - \frac{1}{2}

\int_{0}^{x} e^{x - t} y d t

\int_{0}^{t} x e^{x} d x

\int_{0}^{1} 1 + t^{2} d t

\int_{0}^{2} - x^{2} + 3 x - 2 d x

\int_{2 x}^{x^{2}} e^{- t^{2}} d t

What is the integral from-pi/3 to 0 of sin(x) ?
The integral from-pi/3 to 0 of sin(x) is -1/2