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Popular >

integral from-1 to 1 of (2x+1)

Solution

\int_{- 1}^{1} (2 x + 1) d x

Solution

2

Solution steps

\int_{- 1}^{1} 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 x d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} 2 x d x = 0

\int_{- 1}^{1} 1 d x = 2

= 0 + 2

Simplify

= 2

Popular Examples

integral from 1 to 6 of 2x

\int_{1}^{6} 2 x d x

integral from 2 to 6 of x^2-7x+6

\int_{2}^{6} x^{2} - 7 x + 6 d x

integral from 5 to 8 of 10log_{4}(t)

\int_{5}^{8} 10 lo g_{4} (t) d t

integral from-3 to 2 of 1

\int_{- 3}^{2} 1 d x

integral from 1 to 3 of x^2+2x-3

\int_{1}^{3} x^{2} + 2 x - 3 d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (2x+1) ?
The integral from-1 to 1 of (2x+1) is 2