What is the integral from 50 to 100 of x/(15+4x^2) ?

The integral from 50 to 100 of x/(15+4x^2) is 1/8 ln(8003/2003)

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integral from 50 to 100 of x/(15+4x^2)

\int_{50}^{100} \frac{x}{15 + 4 x ^{2}} d x

\frac{1}{8} ln (\frac{8003}{2003})

Decimal Notation

0.17314 \dots

Solution steps

\int_{50}^{100} \frac{x}{15 + 4 x ^{2}} d x

Apply u-substitution

: \int_{10015}^{40015} \frac{1}{8 u} d u

= \int_{10015}^{40015} \frac{1}{8 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int_{10015}^{40015} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{8} [ln ∣ u ∣]_{10015}^{40015}

Compute the boundaries:

ln (40015) - ln (10015)

= \frac{1}{8} (ln (40015) - ln (10015))

Simplify

= \frac{1}{8} ln (\frac{8003}{2003})

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What is the integral from 50 to 100 of x/(15+4x^2) ?
The integral from 50 to 100 of x/(15+4x^2) is 1/8 ln(8003/2003)