What is the integral from-1 to 1 of-x^2 ?

The integral from-1 to 1 of-x^2 is -2/3

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integral from-1 to 1 of-x^2

\int_{- 1}^{1} - x^{2} d x

- \frac{2}{3}

Decimal Notation

- 0.66666 \dots

Solution steps

\int_{- 1}^{1} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- 1}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{1}

= - [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= - \frac{2}{3}

\int_{- 3}^{1} (x^{2} + x - 2) d x

\int_{- 2}^{3} \frac{x - 3}{4} d x

\int_{0}^{1} e^{\frac{- x ^{2}}{2}} d x

\int_{0}^{3} \frac{x}{7 + x ^{2}} d x

\int_{0}^{1} \frac{x}{x + 1} d x

What is the integral from-1 to 1 of-x^2 ?
The integral from-1 to 1 of-x^2 is -2/3