What is the integral from 1 to 2 of (5-7x)/(x^3) ?

The integral from 1 to 2 of (5-7x)/(x^3) is -13/8

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integral from 1 to 2 of (5-7x)/(x^3)

\int_{1}^{2} \frac{5 - 7 x}{x ^{3}} d x

- \frac{13}{8}

Decimal Notation

- 1.625

Solution steps

\int_{1}^{2} \frac{5 - 7 x}{x ^{3}} d x

Expand

\frac{5 - 7 x}{x ^{3}} : \frac{5}{x ^{3}} - \frac{7}{x ^{2}}

= \int_{1}^{2} \frac{5}{x ^{3}} - \frac{7}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{5}{x ^{3}} d x - \int_{1}^{2} \frac{7}{x ^{2}} d x

\int_{1}^{2} \frac{5}{x ^{3}} d x = \frac{15}{8}

\int_{1}^{2} \frac{7}{x ^{2}} d x = \frac{7}{2}

= \frac{15}{8} - \frac{7}{2}

Simplify

\frac{15}{8} - \frac{7}{2} : - \frac{13}{8}

= - \frac{13}{8}

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What is the integral from 1 to 2 of (5-7x)/(x^3) ?
The integral from 1 to 2 of (5-7x)/(x^3) is -13/8