What is the integral from-5 to 0 of 2+sqrt(25-x^2) ?

The integral from-5 to 0 of 2+sqrt(25-x^2) is 10+(25pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-5 to 0 of 2+sqrt(25-x^2)

\int_{- 5}^{0} 2 + 25 - x^{2} d x

10 + \frac{25 π}{4}

Decimal Notation

29.63495 \dots

Solution steps

\int_{- 5}^{0} 2 + 25 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 5}^{0} 2 d x + \int_{- 5}^{0} 25 - x^{2} d x

\int_{- 5}^{0} 2 d x = 10

\int_{- 5}^{0} 25 - x^{2} d x = \frac{25 π}{4}

= 10 + \frac{25 π}{4}

\int_{0}^{x c o s (x)} 25 - t^{2} d t

\int_{0}^{4} x^{2} - 4 d x

\int_{2}^{5} 3^{5 x} d x

\int_{- 2}^{- 1} \frac{1}{x ^{2}} d x

\int_{0}^{1} (- x + 1)^{2} d x

What is the integral from-5 to 0 of 2+sqrt(25-x^2) ?
The integral from-5 to 0 of 2+sqrt(25-x^2) is 10+(25pi)/4