What is the integral from 0 to 3 of (2x) ?

The integral from 0 to 3 of (2x) is 9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of (2x)

\int_{0}^{3} (2 x) d x

9

Solution steps

\int_{0}^{3} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{3} x d x

Apply the Power Rule

= 2 [\frac{x ^{2}}{2}]_{0}^{3}

Compute the boundaries:

\frac{9}{2}

= 2 \cdot \frac{9}{2}

Simplify

= 9

\int_{0}^{2} (1 - x^{2}) d x

\int_{1}^{\infty} 8 x^{- 9} d x

\int_{1}^{2} \frac{1}{x ^{2} - 3 x + 2} d x

\int_{0}^{1} x^{2} - 2 x d x

\int_{0}^{6} (x^{2} - 6 x) d x

What is the integral from 0 to 3 of (2x) ?
The integral from 0 to 3 of (2x) is 9