What is the integral from 0 to 2 of 3x^5 ?

The integral from 0 to 2 of 3x^5 is 32

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integral from 0 to 2 of 3x^5

\int_{0}^{2} 3 x^{5} d x

32

Solution steps

\int_{0}^{2} 3 x^{5} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{2} x^{5} d x

Apply the Power Rule

: [\frac{x ^{6}}{6}]_{0}^{2}

= 3 [\frac{x ^{6}}{6}]_{0}^{2}

Compute the boundaries:

\frac{32}{3}

= 3 \cdot \frac{32}{3}

Simplify

= 32

\int \frac{10}{sec ( 2 x ) - 1} d x

f (x) = \frac{ln ( x )}{x - 1}

\int (2 t + 7)^{2.9} d t

3 x^{3} - 5 x + 7 x^{4} - 9 - x^{2}

f (x) = - 3 x^{2} + 4 x + 20

What is the integral from 0 to 2 of 3x^5 ?
The integral from 0 to 2 of 3x^5 is 32