What is the integral from-(2pi)/3 to 0 of sin(x) ?

The integral from-(2pi)/3 to 0 of sin(x) is -3/2

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integral from-(2pi)/3 to 0 of sin(x)

\int_{- \frac{2 π}{3}}^{0} sin (x) d x

- \frac{3}{2}

Decimal Notation

- 1.5

Solution steps

\int_{- \frac{2 π}{3}}^{0} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- \frac{2 π}{3}}^{0}

Compute the boundaries:

- \frac{3}{2}

= - \frac{3}{2}

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What is the integral from-(2pi)/3 to 0 of sin(x) ?
The integral from-(2pi)/3 to 0 of sin(x) is -3/2