What is the integral from 1 to infinity of arctan(x) ?

The integral from 1 to infinity of arctan(x) is diverges

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integral from 1 to infinity of arctan(x)

\int_{1}^{\infty} arctan (x) d x

diverges

Solution steps

\int_{1}^{\infty} arctan (x) d x

Compute the indefinite integral:

\int arctan (x) d x = x arctan (x) - \frac{1}{2} ln x^{2} + 1 + C

Compute the boundaries:

\int_{1}^{\infty} arctan (x) d x =

diverges

= diverges

\int_{1}^{2} ∣ x ∣ d x

\int_{1}^{7} \frac{e ^{\frac{7}{x}}}{x ^{2}} d x

\int_{0}^{4} 16 - t^{2} d t

\int_{0}^{4} (7 x + x) d x

\int_{0}^{1} x sin (πn x) d x

What is the integral from 1 to infinity of arctan(x) ?
The integral from 1 to infinity of arctan(x) is diverges