What is the integral from 3 to x of (sin(t))/t ?

The integral from 3 to x of (sin(t))/t is \Si(x)-1.84865…

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integral from 3 to x of (sin(t))/t

\int_{3}^{x} \frac{sin ( t )}{t} d t

Si (x) - 1.84865 \dots

Solution steps

\int_{3}^{x} \frac{sin ( t )}{t} d t

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (t)]_{3}^{x}

Compute the boundaries:

Si (x) - 1.84865 \dots

= Si (x) - 1.84865 \dots

\int_{- 1}^{1} - 2 x^{2} + 2 d x

\int_{0}^{1} sin (x^{4}) d x

\int_{- 1}^{1} x^{2} 4 + x^{2} d x

\int_{x}^{x^{2}} ln (x) d x

\int_{x^{5}}^{x^{6}} (2 t - 1)^{3} d t

What is the integral from 3 to x of (sin(t))/t ?
The integral from 3 to x of (sin(t))/t is \Si(x)-1.84865…