What is the integral from 1 to 6 of (2/x) ?

The integral from 1 to 6 of (2/x) is 2ln(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 6 of (2/x)

\int_{1}^{6} (\frac{2}{x}) d x

2 ln (6)

Decimal Notation

3.58351 \dots

Solution steps

\int_{1}^{6} \frac{2}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{6} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 2 [ln ∣ x ∣]_{1}^{6}

Compute the boundaries:

ln (6)

= 2 ln (6)

\int_{0}^{π} 3 sin (\frac{x}{3}) d x

\int_{0}^{5} \frac{1}{x - 2} d x

\int_{x}^{3 π} cos (t^{2}) d t

\int_{- 1}^{4} x^{2} - 4 x - 5 d x

\int_{2}^{4} 6 x d x

What is the integral from 1 to 6 of (2/x) ?
The integral from 1 to 6 of (2/x) is 2ln(6)