What is the integral from 0 to 2pi of sin^2(θ)cos(θ) ?

The integral from 0 to 2pi of sin^2(θ)cos(θ) is 0

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integral from 0 to 2pi of sin^2(θ)cos(θ)

\int_{0}^{2 π} sin^{2} (θ) cos (θ) d θ

0

Solution steps

\int_{0}^{2 π} sin^{2} (θ) cos (θ) d θ

Compute the indefinite integral:

\int sin^{2} (θ) cos (θ) d θ = \frac{sin ^{3} ( θ )}{3} + C

Compute the boundaries:

\int_{0}^{2 π} sin^{2} (θ) cos (θ) d θ = 0 - 0

= 0 - 0

Simplify

= 0

\int_{- 1}^{1} \frac{1}{1 - x} d x

\int_{0}^{4} (5 x^{2} + x) d x

\int_{0}^{\frac{π}{2}} 3 sin (2 x) d x

\int_{0}^{a} sin^{2} (\frac{2 π x}{a}) d x

\int_{0}^{a} sin^{2} (x) d x

What is the integral from 0 to 2pi of sin^2(θ)cos(θ) ?
The integral from 0 to 2pi of sin^2(θ)cos(θ) is 0