What is the integral from-pi/4 to-pi/6 of cos(x) ?

The integral from-pi/4 to-pi/6 of cos(x) is -1/2+1/(sqrt(2))

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integral from-pi/4 to-pi/6 of cos(x)

\int_{- \frac{π}{4}}^{- \frac{π}{6}} cos (x) d x

- \frac{1}{2} + \frac{1}{2}

Decimal Notation

0.20710 \dots

Solution steps

\int_{- \frac{π}{4}}^{- \frac{π}{6}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{- \frac{π}{4}}^{- \frac{π}{6}}

Compute the boundaries:

- \frac{1}{2} + \frac{1}{2}

= - \frac{1}{2} + \frac{1}{2}

\int_{2}^{4} (x^{2} - 4)^{\frac{3}{2}} d x

\int_{0}^{t^{4}} u d u

\int_{- 1}^{2} (2 x - 1) d x

\int_{0}^{5} k x^{\frac{3}{2}} d x

\int_{0}^{π} 2 cos (x) d x

What is the integral from-pi/4 to-pi/6 of cos(x) ?
The integral from-pi/4 to-pi/6 of cos(x) is -1/2+1/(sqrt(2))