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Popular >

integral from 1 to 2 of (x^2+3)

Solution

\int_{1}^{2} (x^{2} + 3) d x

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

\int_{1}^{2} x^{2} + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} 3 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 3 d x = 3

= \frac{7}{3} + 3

Simplify

\frac{7}{3} + 3 : \frac{16}{3}

= \frac{16}{3}

Popular Examples

integral from-2 to 3 of 4-x^2

\int_{- 2}^{3} 4 - x^{2} d x

integral from 0 to 2pi of (sin^2(x))

\int_{0}^{2 π} (sin^{2} (x)) d x

integral from 1 to 5 of (x^3-1)/(x^3)

\int_{1}^{5} \frac{x ^{3} - 1}{x ^{3}} d x

integral from-2 to x of (14t^2-13t)

\int_{- 2}^{x} (14 t^{2} - 13 t) d t

integral from-1 to 1 of (3x^2-5x+1)/4

\int_{- 1}^{1} \frac{3 x ^{2} - 5 x + 1}{4} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x^2+3) ?
The integral from 1 to 2 of (x^2+3) is 16/3