What is the integral from-pi/2 to pi of sin(x) ?

The integral from-pi/2 to pi of sin(x) is 1

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integral from-pi/2 to pi of sin(x)

\int_{- \frac{π}{2}}^{π} sin (x) d x

1

Solution steps

\int_{- \frac{π}{2}}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- \frac{π}{2}}^{π}

Compute the boundaries:

1

= 1

\int_{0}^{\frac{π}{2}} sin (n x) d x

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\int_{0}^{6} \frac{x}{36 - x ^{2}} d x

\int_{0}^{1} x 75 x^{2} + 25 d x

What is the integral from-pi/2 to pi of sin(x) ?
The integral from-pi/2 to pi of sin(x) is 1