What is the integral from 0 to t of (sin(t))/t ?

The integral from 0 to t of (sin(t))/t is \Si(t)

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integral from 0 to t of (sin(t))/t

\int_{0}^{t} \frac{sin ( t )}{t} d t

Si (t)

Solution steps

\int_{0}^{t} \frac{sin ( t )}{t} d t

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (t)]_{0}^{t}

Compute the boundaries:

Si (t)

= Si (t)

\int_{1}^{2} \frac{x ^{3} + 1}{x} d x

\int_{0}^{1} \frac{y}{2} d y

\int_{0}^{1} (6 t)^{2} + (6 t^{2})^{2} d t

\int_{0}^{2} \frac{1}{x ^{3} + 1} d x

\int_{0}^{3} 2 x^{2} - 6 x d x

What is the integral from 0 to t of (sin(t))/t ?
The integral from 0 to t of (sin(t))/t is \Si(t)