What is the integral from 1 to 27 of 1/(\sqrt[3]{x)} ?

The integral from 1 to 27 of 1/(\sqrt[3]{x)} is 12

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integral from 1 to 27 of 1/(\sqrt[3]{x)}

12

Solution steps

Apply the Power Rule

: [\frac{3}{2} x^{\frac{2}{3}}]_{1}^{27}

= [\frac{3}{2} x^{\frac{2}{3}}]_{1}^{27}

Compute the boundaries:

12

= 12

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What is the integral from 1 to 27 of 1/(\sqrt[3]{x)} ?
The integral from 1 to 27 of 1/(\sqrt[3]{x)} is 12