What is the integral from pi/6 to pi/3 of sec^2(x) ?

The integral from pi/6 to pi/3 of sec^2(x) is sqrt(3)-1/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from pi/6 to pi/3 of sec^2(x)

\int_{\frac{π}{6}}^{\frac{π}{3}} sec^{2} (x) d x

3 - \frac{1}{3}

Decimal Notation

1.15470 \dots

Solution steps

\int_{\frac{π}{6}}^{\frac{π}{3}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{\frac{π}{6}}^{\frac{π}{3}}

Compute the boundaries:

3 - \frac{1}{3}

= 3 - \frac{1}{3}

\int_{0}^{1} x e^{\frac{- x ^{2}}{2}} d x

\int_{0}^{5} x^{4} d x

\int_{0}^{\frac{π}{4}} t^{2} sin (4 t) d t

\int_{- 1}^{1} (4 x^{3} - e^{2 x}) d x

\int_{0}^{1} 30 x^{2} (1 - x)^{2} d x

What is the integral from pi/6 to pi/3 of sec^2(x) ?
The integral from pi/6 to pi/3 of sec^2(x) is sqrt(3)-1/(sqrt(3))