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Popular >

integral from-1 to 0 of (-x-1)

Solution

\int_{- 1}^{0} (- x - 1) d x

Solution

- \frac{1}{2}

+1

Solution steps

\int_{- 1}^{0} - x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{0} x d x - \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} x d x = - \frac{1}{2}

\int_{- 1}^{0} 1 d x = 1

= - (- \frac{1}{2}) - 1

Simplify

- (- \frac{1}{2}) - 1 : - \frac{1}{2}

= - \frac{1}{2}

Popular Examples

integral from 1 to e^x of 1/t

\int_{1}^{e^{x}} \frac{1}{t} d t

integral from 0 to x/n of n(1-x)^{n-1}

\int_{0}^{\frac{x}{n}} n (1 - x)^{n - 1} d x

integral from 0 to pi/2 of xcos(nx)

\int_{0}^{\frac{π}{2}} x cos (n x) d x

integral from x^4 to x^5 of (2t-1)^3

\int_{x^{4}}^{x^{5}} (2 t - 1)^{3} d t

integral from 0 to sin(x) of sqrt(1+t^2)

\int_{0}^{s i n (x)} 1 + t^{2} d t

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of (-x-1) ?
The integral from-1 to 0 of (-x-1) is -1/2