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Popular >

integral from-4 to 1 of |x+2|

Solution

\int_{- 4}^{1} ∣ x + 2 ∣ d x

Solution

\frac{13}{2}

+1

Decimal Notation

6.5

Solution steps

\int_{- 4}^{1} ∣ x + 2 ∣ d x

Eliminate Absolutes

= \int_{- 4}^{- 2} - x - 2 d x + \int_{- 2}^{1} x + 2 d x

\int_{- 4}^{- 2} - x - 2 d x = 2

\int_{- 2}^{1} x + 2 d x = \frac{9}{2}

= 2 + \frac{9}{2}

Simplify

2 + \frac{9}{2} : \frac{13}{2}

= \frac{13}{2}

Popular Examples

integral from-1 to 2 of e^{3x}

\int_{- 1}^{2} e^{3 x} d x

integral from 0 to 2 of 8r^2-2r^4

\int_{0}^{2} 8 r^{2} - 2 r^{4} d r

integral from 4 to 14 of 5e^{0.02t}

\int_{4}^{14} 5 e^{0.02 t} d t

integral from 0 to 8 of x/(sqrt(36+x^2))

\int_{0}^{8} \frac{x}{36 + x ^{2}} d x

integral from 1 to 4 of e^{2x}

\int_{1}^{4} e^{2 x} d x

Frequently Asked Questions (FAQ)

What is the integral from-4 to 1 of |x+2| ?
The integral from-4 to 1 of |x+2| is 13/2