What is the integral from 0 to 4 of 1/(x-2) ?

The integral from 0 to 4 of 1/(x-2) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of 1/(x-2)

\int_{0}^{4} \frac{1}{x - 2} d x

diverges

Solution steps

\int_{0}^{4} \frac{1}{x - 2} d x

Find undefined (singularity) points:

x = 2

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{2} \frac{1}{x - 2} d x + \int_{2}^{4} \frac{1}{x - 2} d x

\int_{0}^{2} \frac{1}{x - 2} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{3}^{\infty} \frac{1}{x ^{5}} d x

\int_{0}^{1} e^{t x} 2 x d x

\int_{0}^{2} 8 x - x^{4} d x

\int_{2}^{4} (2 x + 3) d x

\int_{0}^{1} x arccot (x) d x

What is the integral from 0 to 4 of 1/(x-2) ?
The integral from 0 to 4 of 1/(x-2) is diverges