en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of |3x-9|

Solution

\int_{1}^{4} ∣ 3 x - 9 ∣ d x

Solution

\frac{15}{2}

+1

Solution steps

\int_{1}^{4} ∣ 3 x - 9 ∣ d x

Eliminate Absolutes

= \int_{1}^{3} - 3 x + 9 d x + \int_{3}^{4} 3 x - 9 d x

\int_{1}^{3} - 3 x + 9 d x = 6

\int_{3}^{4} 3 x - 9 d x = \frac{3}{2}

= 6 + \frac{3}{2}

Simplify

6 + \frac{3}{2} : \frac{15}{2}

= \frac{15}{2}

Popular Examples

integral from b to a of x

\int_{b}^{a} x d x

integral from 1/2 to 1 of ycos^2(xy)

\int_{\frac{1}{2}}^{1} y cos^{2} (x y) d x

integral from-2 to 2 of (4-y^2)

\int_{- 2}^{2} (4 - y^{2}) d y

integral from 1 to 3 of x/((x^2+7)^3)

\int_{1}^{3} \frac{x}{( x ^{2} + 7 ) ^{3}} d x

integral from 5 to 6 of 2^{-x}

\int_{5}^{6} 2^{- x} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of |3x-9| ?
The integral from 1 to 4 of |3x-9| is 15/2