What is the integral from-(2pi)/3 to pi/3 of sin(x) ?

The integral from-(2pi)/3 to pi/3 of sin(x) is -1

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integral from-(2pi)/3 to pi/3 of sin(x)

\int_{- \frac{2 π}{3}}^{\frac{π}{3}} sin (x) d x

- 1

Solution steps

\int_{- \frac{2 π}{3}}^{\frac{π}{3}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- \frac{2 π}{3}}^{\frac{π}{3}}

Compute the boundaries:

- 1

= - 1

\int_{- 1}^{1} x^{2} ln ∣ x ∣ d x

\int_{0}^{1} x^{1} d x

\int_{1}^{e^{x}} 7 ln (t) d t

\int_{0}^{1} 4 arctan (- x) d x

\int_{1}^{4} \frac{x + 1}{x} d x

What is the integral from-(2pi)/3 to pi/3 of sin(x) ?
The integral from-(2pi)/3 to pi/3 of sin(x) is -1