What is the tangent of f(x)=3x^2+2x-10,\at x=1 ?

The tangent of f(x)=3x^2+2x-10,\at x=1 is y=8x-13

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tangent of f(x)=3x^2+2x-10,\at x=1

tangent of

f (x) = 3 x^{2} + 2 x - 10, at x = 1

y = 8 x - 13

Solution steps

Find the tangent point:

(1, - 5)

Find the slope of

f (x) = 3 x^{2} + 2 x - 10 : \frac{df ( x )}{d x} = 6 x + 2

Compute the slope of

f (x) = 3 x^{2} + 2 x - 10

x = 1 : m = 8

Find the line with slope m=

8

and passing through

(1, - 5) : y = 8 x - 13

y = 8 x - 13

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What is the tangent of f(x)=3x^2+2x-10,\at x=1 ?
The tangent of f(x)=3x^2+2x-10,\at x=1 is y=8x-13