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Popular >

integral from 0 to 5 of |x-4|

Solution

\int_{0}^{5} ∣ x - 4 ∣ d x

Solution

\frac{17}{2}

+1

Solution steps

\int_{0}^{5} ∣ x - 4 ∣ d x

Eliminate Absolutes

= \int_{0}^{4} - x + 4 d x + \int_{4}^{5} x - 4 d x

\int_{0}^{4} - x + 4 d x = 8

\int_{4}^{5} x - 4 d x = \frac{1}{2}

= 8 + \frac{1}{2}

Simplify

8 + \frac{1}{2} : \frac{17}{2}

= \frac{17}{2}

Popular Examples

integral from 0 to x of te^{2t^2}

\int_{0}^{x} t e^{2 t^{2}} d t

integral from 0 to 1 of x^2-2x+1

\int_{0}^{1} x^{2} - 2 x + 1 d x

integral from 1 to 3 of-x^2+4

\int_{1}^{3} - x^{2} + 4 d x

integral from 2 to 1 of 1/x

\int_{2}^{1} \frac{1}{x} d x

integral from 0 to pi/3 of 5sin(x/2)

\int_{0}^{\frac{π}{3}} 5 sin (\frac{x}{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of |x-4| ?
The integral from 0 to 5 of |x-4| is 17/2