What is the integral from 8 to 125 of \sqrt[3]{x} ?

The integral from 8 to 125 of \sqrt[3]{x} is 1827/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 8 to 125 of \sqrt[3]{x}

\frac{1827}{4}

Solution steps

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{8}^{125}

= [\frac{3}{4} x^{\frac{4}{3}}]_{8}^{125}

Compute the boundaries:

\frac{1827}{4}

= \frac{1827}{4}

\int_{1}^{3} (x^{2} - 8 x + 15) d x

\int_{0}^{5} - 4 x d x

\int_{0}^{x} \frac{e ^{2 s} - 1}{s} d s

\int_{1}^{4} 4^{5 x} d x

\int_{2}^{3} 24 - 8 x d x

What is the integral from 8 to 125 of \sqrt[3]{x} ?
The integral from 8 to 125 of \sqrt[3]{x} is 1827/4