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Popular >

integral from 0 to 6 of (x^2+1)

Solution

\int_{0}^{6} (x^{2} + 1) d x

Solution

78

Solution steps

\int_{0}^{6} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} x^{2} d x + \int_{0}^{6} 1 d x

\int_{0}^{6} x^{2} d x = 72

\int_{0}^{6} 1 d x = 6

= 72 + 6

Simplify

= 78

Popular Examples

integral from 0 to 2 of 1/(x+4)

\int_{0}^{2} \frac{1}{x + 4} d x

integral from 1 to 6 of t^2-2t-8

\int_{1}^{6} t^{2} - 2 t - 8 d t

integral from 1 to-1 of x^2

\int_{1}^{- 1} x^{2} d x

integral from 0 to 3 of 1/(1+x)

\int_{0}^{3} \frac{1}{1 + x} d x

integral from x^2 to sqrt(x of)(x^2+y^2)

\int_{x^{2}}^{x} (x^{2} + y^{2}) d y

Frequently Asked Questions (FAQ)

What is the integral from 0 to 6 of (x^2+1) ?
The integral from 0 to 6 of (x^2+1) is 78