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Popular >

integral from-2 to 1 of (x+1)^2-1

Solution

\int_{- 2}^{1} (x + 1)^{2} - 1 d x

Solution

0

Solution steps

\int_{- 2}^{1} (x + 1)^{2} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} (x + 1)^{2} d x - \int_{- 2}^{1} 1 d x

\int_{- 2}^{1} (x + 1)^{2} d x = 3

\int_{- 2}^{1} 1 d x = 3

= 3 - 3

Simplify

= 0

Popular Examples

integral from-1 to 1 of-3x^2+3

\int_{- 1}^{1} - 3 x^{2} + 3 d x

integral from 0 to 1-x of 1

\int_{0}^{1 - x} 1 d y

integral from 0 to 1 of x/(x^2-x+1)

\int_{0}^{1} \frac{x}{x ^{2} - x + 1} d x

integral from 0 to a of (ax^2-x^3)

\int_{0}^{a} (a x^{2} - x^{3}) d x

integral from 1/2 to 1 of (x^{-3}-7)

\int_{\frac{1}{2}}^{1} (x^{- 3} - 7) d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 1 of (x+1)^2-1 ?
The integral from-2 to 1 of (x+1)^2-1 is 0