What is the integral from 1 to e of ((1+ln(x)))/x ?

The integral from 1 to e of ((1+ln(x)))/x is 3/2

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integral from 1 to e of ((1+ln(x)))/x

\int_{1}^{e} \frac{( 1 + ln ( x ) )}{x} d x

\frac{3}{2}

Solution steps

\int_{1}^{e} \frac{1 + ln ( x )}{x} d x

Apply u-substitution

: \int_{1}^{2} u d u

= \int_{1}^{2} u d u

Apply the Power Rule

: [\frac{u ^{2}}{2}]_{1}^{2}

= [\frac{u ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= \frac{3}{2}

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What is the integral from 1 to e of ((1+ln(x)))/x ?
The integral from 1 to e of ((1+ln(x)))/x is 3/2