What is (\partial)/(\partial x)(3e^{2x}-5ln(y)+7) ?

The answer to (\partial)/(\partial x)(3e^{2x}-5ln(y)+7) is 6e^{2x}

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(\partial)/(\partial x)(3e^{2x}-5ln(y)+7)

\frac{\partial}{\partial x} (3 e^{2 x} - 5 ln (y) + 7)

6 e^{2 x}

Solution steps

\frac{\partial}{\partial x} (3 e^{2 x} - 5 ln (y) + 7)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 e^{2 x}) - \frac{\partial}{\partial x} (5 ln (y)) + \frac{\partial}{\partial x} (7)

\frac{\partial}{\partial x} (3 e^{2 x}) = 6 e^{2 x}

\frac{\partial}{\partial x} (5 ln (y)) = 0

\frac{\partial}{\partial x} (7) = 0

= 6 e^{2 x} - 0 + 0

Simplify

= 6 e^{2 x}

\int_{2}^{7} x d x

\frac{d y}{d x} = (\frac{3 y + 2}{5 x + 4})^{2}

\int ln (2 x) d x

\frac{\partial}{\partial x} (sin (4 x))

\int_{0}^{3} (3 - x) d x

What is (\partial)/(\partial x)(3e^{2x}-5ln(y)+7) ?
The answer to (\partial)/(\partial x)(3e^{2x}-5ln(y)+7) is 6e^{2x}