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Popular >

integral from 1 to 2 of (x^3+1)

Solution

\int_{1}^{2} (x^{3} + 1) d x

Solution

\frac{19}{4}

+1

Solution steps

\int_{1}^{2} x^{3} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{3} d x + \int_{1}^{2} 1 d x

\int_{1}^{2} x^{3} d x = \frac{15}{4}

\int_{1}^{2} 1 d x = 1

= \frac{15}{4} + 1

Simplify

\frac{15}{4} + 1 : \frac{19}{4}

= \frac{19}{4}

Popular Examples

integral from-1 to 1 of sqrt(1-y^2)

\int_{- 1}^{1} 1 - y^{2} d y

integral from 1 to e^x of 3ln(t)

\int_{1}^{e^{x}} 3 ln (t) d t

integral from 0 to 1 of 12xy(1-x)

\int_{0}^{1} 12 x y (1 - x) d x

integral from 1 to y of y/x

\int_{1}^{y} \frac{y}{x} d x

integral from 3 to 4.3 of (12x^2-6x+4)

\int_{3}^{4.3} (12 x^{2} - 6 x + 4) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x^3+1) ?
The integral from 1 to 2 of (x^3+1) is 19/4