What is the integral from 1 to 3 of 1/2 ?

The integral from 1 to 3 of 1/2 is 1

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integral from 1 to 3 of 1/2

\int_{1}^{3} \frac{1}{2} d x

1

Solution steps

\int_{1}^{3} \frac{1}{2} d x

Integral of a constant:

\int a d x = a x

= [\frac{1}{2} x]_{1}^{3}

Compute the boundaries:

1

= 1

\int_{3}^{6} (x^{2} - 6 x + 9) d x

\int_{0}^{l n (A)} 9 e^{3 x} d x

\int_{1}^{2} \frac{x}{3} d x

\int_{\frac{π}{6}}^{\frac{π}{3}} sin^{2} (x) d x

\int_{1}^{2} (3 x + 2) d x