What is the integral from 0 to cos(θ) of sec^2(y) ?

The integral from 0 to cos(θ) of sec^2(y) is tan(cos(θ))

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integral from 0 to cos(θ) of sec^2(y)

\int_{0}^{c o s (θ)} sec^{2} (y) d y

tan (cos (θ))

Solution steps

\int_{0}^{c o s (θ)} sec^{2} (y) d y

Use the common integral:

\int sec^{2} (y) d y = tan (y)

= [tan (y)]_{0}^{c o s (θ)}

Compute the boundaries:

tan (cos (θ))

= tan (cos (θ))

\int_{0}^{4} 3 x - 8 d x

\int_{0}^{2} - x + 2 d x

\int_{2}^{52} r d r

\int_{0}^{3} - x^{2} + 4 d x

\int_{0}^{4} (x - 5) (x - 1) d x

What is the integral from 0 to cos(θ) of sec^2(y) ?
The integral from 0 to cos(θ) of sec^2(y) is tan(cos(θ))